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dS = ÎŒS dt + ÏS dW
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âV/ât + (1/2)ϲS²â²V/âS² + rSâV/âS – rV = 0
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V(S,t) = E^Q[e^(-r(T-t)) Payoff(S_T)]
ããã§E^Qã¯ãªã¹ã¯äžç«æž¬åºŠã§ã®æåŸ å€ãPayoffã¯æºæTã§ã®ãªãã·ã§ã³ã®ãã€ãªã颿°ãªã®ãããã³ãŒã«ãªãã·ã§ã³ãªã Payoff = max(S_T – K, 0)ãããããªãã·ã§ã³ãªã Payoff = max(K – S_T, 0) ãšãªãããã
ðå ·äœäŸïŒãšãŒããã¢ã³ã³ãŒã«ãªãã·ã§ã³ã®äŸ¡æ Œèšç®
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- æš©å©è¡äœ¿äŸ¡æ Œ K = 10,500å
- æºæãŸã§ã®æé T = 0.5幎ïŒ6ã¶æïŒ
- ãã©ãã£ãªãã£ Ï = 0.25ïŒå¹Žç25%ïŒ
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C = SâN(dâ) – Ke^(-rT)N(dâ)
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dâ = [ln(Sâ/K) + (r + ϲ/2)T] / (ÏâT) dâ = dâ – ÏâT
N(x)ã¯æšæºæ£èŠååžã®çޝç©ååžé¢æ°ãªã®ããããå®éã«ä»£å ¥ãããšïŒ
dâ = [ln(10000/10500) + (0.02 + 0.25²/2)Ã0.5] / (0.25Ãâ0.5) = [-0.0488 + 0.0256] / 0.1768 = -0.131
dâ = -0.131 – 0.1768 = -0.308
N(-0.131) â 0.448ãN(-0.308) â 0.379 ãªã®ã§ã
C = 10000Ã0.448 – 10500Ãe^(-0.01)Ã0.379 = 4480 – 10500Ã0.990Ã0.379 = 4480 – 3940 = çŽ540å
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å ã»ã©ã®äŸã§ãæ ªäŸ¡ã®çµè·¯ã10äžåã·ãã¥ã¬ãŒãããæ¹æ³ãèŠãŠã¿ããããæéã现ããå»ãã§ïŒäŸãã°1æ¥ããšã«ïŒãæ ªäŸ¡ã®å€åãæ¬¡ã®åŒã§èšç®ããã®ããïŒ
S(t+Ît) = S(t) à exp[(r – ϲ/2)Ît + ÏâÎt à Z]
ããã§Zã¯æšæºæ£èŠååžã«åŸãä¹±æ°ïŒå¹³å0ã忣1ïŒãªã®ãããÎt = 1/250ïŒå¶æ¥æ¥ããŒã¹ïŒãšããŠã125æ¥åã®çµè·¯ãã·ãã¥ã¬ãŒãããã®ãããã
ð»ââïžã10äžæ¬ã®çµè·¯ãçæããŠãããããã§æºæã®ãã€ãªãmax(S_T – 10500, 0)ãèšç®ãããã®å¹³åã e^(-rT) ã§å²ãåŒãã®ããã
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- çµè·¯1ïŒæºææ ªäŸ¡11,200å â ãã€ãªã700å
- çµè·¯2ïŒæºææ ªäŸ¡9,800å â ãã€ãªã0å
- çµè·¯3ïŒæºææ ªäŸ¡12,500å â ãã€ãªã2,000å
- …ïŒ10äžæ¬ïŒ
- å¹³åãã€ãªãïŒ545å
å²åŒåŸïŒ545 à e^(-0.01) = 545 à 0.990 = çŽ540å
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- æºæ T = 0.5幎
- ãã©ãã£ãªãã£ Ï = 0.25
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- åç §éå©ïŒ6ã¶æLIBORãŸãã¯TIBOR
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